3^4x-5=1/27^2x+10-5

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Solution for 3^4x-5=1/27^2x+10-5 equation: 



3^4x-5=1/27^2x+10-5

We move all terms to the left:

3^4x-5-(1/27^2x+10-5)=0



Domain of the equation: 27^2x+10-5)!=0

We move all terms containing x to the left, all other terms to the right

27^2x-5)!=-10

x∈R



We get rid of parentheses

3^4x-1/27^2x-10+5-5=0

We multiply all the terms by the denominator


3^4x*27^2x-10*27^2x+5*27^2x-5*27^2x-1=0

Wy multiply elements

81x^6-270x^2+135x^2-135x^2-1=0

We do not support expression: x^6

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